![]() Do you still think using structs is a good approach for that? Please ask me for clarifications if necessary. My implementation sounds complicated but what I really do is quite simple. ![]() After that, I need to search the profile struct (timestep_struct(t).profile=profile ), search within every array of that, to find an id (remember we have arrays of Mx3 where the first column is id and the second is a number to be reduced) in other timesteps other than t, and reduce their number by 1. You can use cell to preallocate a cell array to which you assign data later.cell also converts certain types of Java ®. So,zero positions in the cell array have been reduced by one and the position marked as 1 will be no longer be used. To create a cell array with a specified size, use the cell function, described below. When i find the coordinates that give me maximum util, I set that position in the cell array to 1. For each zero position I find the corresponding value from the struct and perform the black box operation. To pass data from a string array to such functions, use the cellstr function to convert the string array to a cell array of character. However, you might need to use functions that accept cell arrays of character vectors as input arguments, and that do not accept string arrays. The way I am doing all this now, is by initializing a cell array having the dimensions of timestep_struct with zero at each position. You can create string arrays to contain multiple pieces of text. Then, i will run the same operation again to find the next best configuration. One of this timestep_struct(i).coordinates(j,:) will give me the maximum utility after the processing. Say t can take values from 1 to 120, and each coordinates matrix may have from 1 to 100 rows (each matrix can have different number of rows). This will be used in let's say black box operation. What i want to do, is to iterate through timestep_struct(t) selecting one row of coordinates at a time. "points" is a 2 columned matrix with N rows. profile for each iteration t, is an array like. This has the same restriction, all the cell contents must have the same number of characters or the command will error.Where it is populated inside a for loop which is fast enough. So as pointed at, if one of your cell contained Foo24 then the reshape command would error.Įdit: Or as Chris Luengo kindly mentionned in comment, a simpler command to get exactly the same result: > cell2mat(FooCellArray.') Mainly because they are not as flexible as strings, each line has to have the same number of elements. ![]() Refer to sets of cells by enclosing indices in smooth parentheses, (). Cell arrays commonly contain either lists of character vectors of different lengths, or mixes of strings and numbers, or numeric arrays of different sizes. This result type is a char array, which are ok when they are simple vector but they get quite unwieldy once they are in 2D. A cell array is a data type with indexed data containers called cells, where each cell can contain any type of data. If you MATLAB version is older AND if all the strings in the cell array have the same length, you could convert your cell array into a 2D character array: > reshape(cell2mat(FooCellArray),4,).'įor this one, transposition wouldn't really make sense. Note the terminology of the result type, it is a string array. You can transpose it if you want it as a column instead of line vector. The benefit of this method is that it will work even if the strings contained in your cell array are not all of the same length. You can directly use the function convertCharsToStrings: > convertCharsToStrings(FooCellArray) With a smaller starting example: FooCellArray = ![]()
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